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The reaction 1/2H(2) (g) +AgCl(s) = H^(+...

The reaction `1/2H_(2) (g) +AgCl(s) = H^(+) (aq) + CI^(-) (aq) + Ag(s)` occurs in the galvanic cell

A

`Ag|AgCl(s)|KCl(aq)|AgN0_(3)(aq)|Ag`

B

`Pt|H_(2)(g)|HCl(aq)||AgN0_(3)(aq)|Ag`

C

`Pt|H_(2)(g)|HCl(aq)||AgCl(s)|Ag`

D

`Pt|H_(2)(g)|KCl(aq)||AgCl(s)|Ag`

Text Solution

Verified by Experts

The correct Answer is:
D
`H_(2)` is oxidized to `H^(+)` and thus it well occur at anode, i.e., left-side electrode `PI|H_(2) (g) HCl(aq)`. AgCl is reduced to Ag and thus it will occur at cathode, i.e.,right-side electrode HCl(aq) AgCl(s) Ag(s). Hence, the cell with these reactions is Pt|H, (g) HCl(aq)|AgCl(s) Ag
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