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Given E(Fe^(3+)//Fe)^(@)=-0.036V and E(f...

Given `E_(Fe^(3+)//Fe)^(@)=-0.036V` and `E_(fe^(2+)//Fe)^(@)=-0.44V` . What is the value of `E_(Fe^(3+)//Fe^(2+))^(@)`

A

(- 0.036 - 0.439) V

B

(- 0.036 + 0.439) V

C

[3 (- 0.036 +2 (- 0.439)] V

D

[3 (- 0.036 - 2 (- 0.439)] V

Text Solution

Verified by Experts

The correct Answer is:
D
`Fe^(3+) +3e^(-) rarrFe`
`Fe^(2+)+2e^(-)rarrFe`
`Fe^(3+)+e^(-)rarrFe^(2+)`
`E^(@)=[3(0.36-2(0.439)]V(therefore triangle G=-nFE)`
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