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The rate law expression of a reaction 2...

The rate law expression of a reaction `2A+B rarr A_(2)B` is rate =`k[A]^(2)` with rate constant k =0.65 `mol^(-1) L s^(-1)`
calculate rate of reaction when
(a) `[A]=0.25 mol L^(-1) [B]=1.84 mol L^(-1)`

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Rate of reaction `r=k[A]^(2)`
Rate =`k[A]^(2) =0.65 mol^(-1) Ls^(-1) xx(0.25 mol L^(-1))^(2) =0.0406 mol L^(-1) s(-1)`
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