In the reduction of nitrous oxide with hydrogen an equimolar mixture of the gases at 340 mm initial pressure was half changed in 120 second in a second experiment when the intial pressure 288 mm the change was half completed in 140 seconds what is the order of reaction

Explanation

Since this is gaseous reaction concentration can be susbtituted by pressures
Thus `(t_(1))/(t_(2))=(a_(2))/(a_(1))^(n-1)=[(p_(2))/(p_(1))]^(n-1)`
`therefore 102/140 =[(288)/(340)]^(n-1) or (n-1) ln 288/340 =ln 102/140 , n =2.9 =3 `
The reaction of the third order