The rate expression for the reaction `A (g) + B (g) rarr C (g)` is rate = `kC_(A)^(2)C_(B)^(1//2)`. What changes in the initial concentrations of A and B will cause the rate of reaction to increase by a factor of eight?

Options

A. `C_(A)xx2,C_(B)xx2`
B. `C_(A)xx2,C_(B)xx4`
C. `C_(A)xx1,C_(B)xx4`
D. `C_(A)xx4C_(B)xx1`

Answer

B

Explanation

Rate =`kC_(A)^(2)C_(B)^(1//2),Rate =k[2C_(A)]^(2)[4C_(B)]^(1//2)=4xx2[C_(A)]^(2)[C_(B)]^(1//2)`