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The rate constant for the reaction, 2N(2...

The rate constant for the reaction, `2N_(2)O_(5) rarr 4NO_(2) +O_(2)` is `3.0 xx10^(-5) s^(-1)` If the rate is `2.40 xx10^(-5)` mo `L^(-1) S^(-1)` then the concentration of `N_(2)O_(5)` (in mo `L^(-1)`) is

A

1.4

B

1.2

C

0.04

D

0.8

Text Solution

Verified by Experts

The correct Answer is:
D

`[N_(2)O_(5)]=r//k=(2.4 xx10^(-5) mol L^(-1) S^(-1))//(3.0xx10^(-5) s^(-1))=0.8 mol L^(-1)`
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