The time `t_(1//4)` can be taken as the time taken for the concentration of a reactant to drop to 3/4th of its initial value. If the rate constant for a first -order reation is k, then `t_(1//4)` can be written as

Options

A. 0.10 /k
B. 0.29 /k
C. 0.69 /k
D. 0.75 / k

Answer

B

Explanation

For a first order reaction `t_(1//4)=(2.303)/(k) log (1)/(1-1//4)=(0.29)/(k)`