Under the same reaction conditions intital concentration of 1.386 mol `dm^(-3)` of a substance becomes half in 40 and 20 through first order and zero order kinetics respectively ratio `(k_(1)//k_(0))` of the rate constants for first order `k_(1)` and zero order `k_(0)` of the reaction is

Options

A. `0.5 mol^(-1) dm^(3)`
B. `1.0 mol dm^(-3)`
C. `1.5 mol dm^(-3)`
D. `2.0 mol^(-1) dm^(3)`

Answer

A

Explanation

Using half life period method for first order reaction `k_(1) =0.693//t_(1//2)=0.693//40`
for zero order reaction `k_(0) =[A]_(0)//2t_(1//2)=0.5 mol^(-1)`