The activation energy for a reaction which doubles the rate when the temperature is raised from 300 K to 310 K is

Options

A. `50.6 kj mol^(-1)`
B. `53.6 kj mol^(-1)`
C. `56.6 kj mol^(-1)`
D. `59.6 kj mol^(-1)`

Answer

B

Explanation

`E_(a)=(2.303RT_(1)T_(2))/(triangleT) log(k_(2))/(k_(1))=536000 j mol^(-1)=53.6 kj mol^(-1)`