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The reaction A + 2B + C rarr D occurs by...

The reaction `A + 2B + C rarr D` occurs by the following mechanism.
`A + B underset(k_(2))overset(k_(1))hArr E` (rapid equilibrium)
`E + C overset(k_(1))rarr` F(slow)
`F + B overset(k_(4))rarr D` (very fast)
The rate law for this reaction is

A

`r=k[c]`

B

`r=k[A][B]^(2)[C]`

C

`r=k[D]`

D

`r=k[A][B][C]`

Text Solution

Verified by Experts

The correct Answer is:
D
From the slow step we write rate -`k_(3)[E][C]`
Hence rate =`k_(3)k_(eq)` [A][B][C]=k[A][B][C]
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