The reaction `A rarrB+C` has rate constant `1xx10^(-3) Ms^(-1)`. If one starts the reaction with one mole of A then `t_(1//2)` and completion of reaction time would be:

Options

A. 1000s , 500 s
B. 500 s, 1000 s
C. 750 s, 400 s
D. 400 s, 800 s

Answer

B

Explanation

This is zero reaction from the values of `k(Ms^(-1))`
`t_(1//2)=(A_(0))/(2K)=(1)/(2xx10^(-3))=500 sec` and `t_(1//2)=[A_(0)]/(k)=(1)/(10^(-3))=1000 sec`