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For first order parallel reactions k(1) ...

For first order parallel reactions `k_(1)` and `k_(2)` are 4 and 2 `min^(- 1)` respectively at 300 K.. If the activation energies for the formation of B and C are respectively 30,000 and 38,314 joule/mol respectively. The temperature at which B and C will be obtained in equimolar ratio is:

A

757.48 k

B

378.74 k

C

600 k

D

450 k

Text Solution

Verified by Experts

The correct Answer is:
B

`In (k_(1))/(k_(1))=(E_(1))/(R )[(1)/(T_(1))-(1)/(T_(2))]`
(for equimolar formation of B and C `k_(2)=k_(1))`
In `(k_(1))/(k_(2))=(8314)/(8.314)(T_(2)-300)/(300xxT_(2)) In 2=(1000)(T_(2)-300)/(300xxT_(2)) T_(2)=378.74 k`
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