At 500 K, the half life period of a gaseous reaction at an initial pressure of 80 kPa is 350 sec. When the pressure is 40 kPa, the half life period is 175 sec, the order of the reaction is:

Options

A. zero
B. one
C. two
D. three

Answer

A

Explanation

`(t_(1//2))/(t_(1//2))_(2)=(p_(2))/(p_(1))^(n-1),350/175=(40/80)^(n-1)`
`2=(1/2)^(n-1) n-1 =-1`