For a reaction A `rarr` Product half-life measured for two different value of intial concentration `5xx10^(-3)` M and `25 xx10^(-4)` M are 1.0 and 8.0 hrs respectively. If initial concentration is adjusted to `1.25 xx10^(-3)` M, the new half-life would be

Options

A. 16 hrs
B. 32 hrs
C. 64 hrs
D. 256 hrs

Answer

C

Explanation

For a `n^("th")` order reaction `t_(1//2) prop (1)/(a_(n-)):a` =intial concentration
`rarr(5xx10^(-3))/(25xx10^(=4))^(n-1) =(8.1) rarr (5xx10^(-3))/(1.25 xx10^(-3))^(n=4)=(t_(1//2))/(1) =64 hrs`