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When the concentration of a reactant in ...

When the concentration of a reactant in reaction A `rarr` B is increased by 8 times but rate increases only 2 times, the order of the reaction would be

A

2

B

`1//3`

C

4

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
B
`r_(1)=l[A]^(n),r_(2)=2r_(1)=k[8A]^(n) therefore (2r_(1))/(r_(1))=(8)^(n)`
`(2)^(1)=(2)^(3n) therefore 3n=1 n=1/3`
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