The decomposition of A into product has value of `k` as `4.5 x10^(3) (s)^(-1)` at `10^oC` and energy of activation'60 kj mol^(-1)`.At what temperature would K be `1.5 x10^(4) (s)^-1 ?`

Options

A. `12^(@)` C
B. `24^(@)` C
C. `48^(@)` C
D. `36^(@)` C

Answer

B

Explanation

Given that `k_(10)=k_(283)=4.5 xx10^(3) S^(-1) k_(T)=1.5 xx10^(4) S^(-1) T=?` also
`log(1.5 xx10^(4)s^(-1))/(4.5 xx10^(3)s^(-1))=(60000 j mol^(-1))/(2.303xx8.3 jk^(-1) mol^(-1))[(T-283)/(283xxT)]`
on solving we get T=297 k = `24^(@)` C