Ce (Z-58) and Yb (Z=70) exhibit stable +4 and +2 oxidation states, respectively. This is because

Options

A. `Ce^(4+)" and " Yb^(2+) " acquire " f^7 " configurations "`
B. `Ce^(4+)" and " Yb^(2+) " acquire " f^0 " configurations "`
C. `Ce^(4+)" and " Yb^(2+) " acquire " f^0 and f^14 " configurations "`
D. `Ce^(4+)" and " Yb^(2+) " acquire " f^7 and f^14 " configurations "`

Answer

C

Explanation

Both acquire stable configurations, that is, `f^0 " and " t^(14)`