All Cu(II) halides are known except iodide. The reason for this is that

Options

A. iodide ion is a bulky ion
B. `Cu^(2+)` oxidizes iodide to iodine
C. `Cu^(2+)`(aq) has much more negative hydration enthalpy
D. `Cu^(2+)` ion has smaller size

Answer

B

Explanation

lodide `(I^-)` ions are stronger reducing agent. They reduce `Cu^(2+)" To " Cu^+ (2CuI_2 to Cu_2 I_2 + I_2)`.
In other words, `Cu^(2+)` oxidizes I-ions to `I_2 (2Cu^(2+) + 4I to Cu_2 I_2 (s) + I_2)`