When `Hg_2 Cl_2`, ionizes, the ions produced and the unpaired electrons present on the cation respectively are

Options

A. `2Hg^+ " and " 2 Cl^-` two
B. `Hg_2^(2+) " and " 2 CI^-`', two
C. `Hg_2^(2+) " and 2 " Cl^-`, one
D. `Hg_2^(2+) " and 2 "Cl^-`, zero .

Answer

D

Explanation

`Hg_2 Cl_2 to Hg_2^(2+) + 2Cl^- ` Each `Hg^+` has one unpalred electron. Hence, `Hg_2^(2+)` has on unpaired electon.