Number of moles of `K_2Cr_2O_7`, reduced by one mole of `Sn^(2+)` ions is:

Options

A. `1//3`
B. `3`
C. `1//6`
D. `6`

Answer

A

Explanation

`Cr_2 O_7^(2+) + 14H^+ to 2Cr^(3+) + 3Sn^(4+) + 7H_2O`
3 mole of `Sn^(2+)` ions will reduce = 1 mole of `Cr_2O_7^(2-)`= 1 mole of ` K_2 Cr2 O_7`
1 mole of `Sn^(2+) ` ions will reduce = 1/3 mole of ` K_2 Cr2 O_7`