Write the formula for tetraammineaquacħloridocobalt(III) chloride.

Explanation

(i) Central metal atom=Co
(ii) Ligands : tetra ammine = `(NH_3)_4`, aqua= `(H_2O)` , chlorido=`(CI^(-))`
(iv)`[Co(NH_3)_4(H_2O)Cl]^x` where x is the charge on the complex ion.
x=Oxidation state of cobalt+Charge on the ligands.
`x = (+3) + 4 xx (0) + (0) + (-1).= +2`
Therefore, the complex ion is : `[Co(NH_3)_4(H_2O)Cl]^(2+)`
Anion or counter ion in this case is: `Cl^(-)` (simple ion).
Evidently, two anions will neutralise the charge on the complex ion.
Hence the formula of the complex is `[Co(NH_3)_4(H_2O)Cl]Cl_(2-)`