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In heterozygous condition, both the alle...

In heterozygous condition, both the alleles express in

A

Colour blindness

B

AB blood group

C

Rh factor

D

A and B blood types

Text Solution

Verified by Experts

The correct Answer is:
B

• The gene (I) has three alleles ,`I^(A),I^(B)` and i. The alleles `I^(A)` and `I^(B)` produce a slightly different form of the sugar while allele i doesn.t produce any sugar.
• Because humans are diploid organisms, each person possesses any two of the three I gene alleles.
• `I^(A)` and `I^(B)` are completely dominant over i, in other words when `I^(A)` and i are present only `I^(A)` expresses (because i does not produce any sugar), and when `I^(B)` and i are present is `I^(B)` expresses.
• But when `I^(A)` and `I^(B)` are present together they both express their own types of sugars: this is because of co-dominance. Hence red blood cells bave both A and B types of sugars.
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