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If 4/(1+sqrt2+sqrt3)=a+b sqrt2+c sqrt3-d...

If `4/(1+sqrt2+sqrt3)=a+b sqrt2+c sqrt3-d sqrt6`, where a, b, c. d are natural numbers, then the value of a + b+ c + d is:
यदि`4/(1+sqrt2+sqrt3)=a+b sqrt2+c sqrt3-d sqrt6` जहां a, b, c ,d प्राकृतिक संख्याएँ है, तो a+b+ c+ d का मान है:

A

0

B

2

C

4

D

1

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