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triangle ABC ~ triangle EDF and AB =5 cm...

`triangle ABC ~ triangle EDF` and AB =5 cm, BC = 8cm and AC = 10cm.If `ar(triangle ABC) : ar(triangle EDF) = 9: 4`,then DF is equal to:
`triangle ABC ~ triangle EDF` है तथा AB = 5cm, BC = 8cm और AC = 10cm है| यदि `ar(triangle ABC) : ar(triangle EDF) = 9: 4`,है, तो DF का मान क्या होगा ?

A

`20/3` cm

B

`32/9` cm

C

`10/3` cm

D

`16/3` cm

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