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In `triangle ABC`, `angle C=90^@`, Points P and Q are on the sides AC and BC, respectively, such that AP :PC =BQ: QC=1:2 Then `(AQ^2+BP^2)/(AB^2)` is equal to:
`triangle ABC` में `angle C=90^@`, बिंदु P और Q क्रमशः AC और BC पर बिंदु इस प्रकार है की AP :PC =BQ: QC=1:2 तो `(AQ^2+BP^2)/(AB^2)` = ?

A

a)`4/7`

B

b)`4/3`

C

c)`13/9`

D

d)`8/3`

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