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If b+c = ax, c+a = by and a+b = cz, then...

If b+c = ax, c+a = by and a+b = cz, then the value of `1/9[1/(x+1)+1/(y+1)+1/(z+1)]` is :
यदि b+c = ax, c+a = by तथा a+b =cz है, तो `1/9[1/(x+1)+1/(y+1)+1/(z+1)]` का मान क्या होगा ?

A

`1/3`

B

0

C

`1/9`

D

1

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PINNACLE-ALGEBRA-EXERCISE
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