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If sec theta=4x and tan theta=4/x, (x ne...

If `sec theta=4x` and `tan theta=4/x`, `(x ne 0)` then the value of `8(x^2-1/x^2)` is:
यदि `sec theta=4x` और `tan theta=4/x`, है जहाँ `(x ne 0)` है, तो `8(x^2-1/x^2)` का मान ज्ञात करें |

A

`1/16`

B

`1/4`

C

`1/2`

D

`1/8`

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