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If 2(cosec^2 39-tan^2 51)- 2/3 sin90 -ta...

If `2(cosec^2 39-tan^2 51)- 2/3 sin90 -tan^2 56y tan^2 34=y/3`, then the value of y is :
यदि `2(cosec^2 39-tan^2 51)- 2/3 sin90 -tan^2 56y tan^2 34=y/3` है, तो y का मान क्या होगा ?

A

1

B

`2/3`

C

`-2/3`

D

`-1`

Text Solution

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