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If sin theta=3x and cos theta=3/x, (x ne...

If `sin theta=3x` and `cos theta=3/x, (x ne 0)` then the value of `6(x^2+ 1/x^2)` is:
यदि `sin theta=3x` और `cos theta=3/x` है, जहाँ `(x ne 0)` है, तो `6(x^2+1/x^2)` मान क्या होगा ?

A

`1/4`

B

`1/2`

C

`1/3`

D

`2/3`

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