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If `cot theta=5x` and `cosec theta= 5/x (x ne 0)`, then the value of `5(x^2- 1/x^2)` is:
यदि `cot theta=5x` तथा `cosec theta= 5/x (x ne 0)` है, तो `5(x^2- 1/x^2)` का मान ज्ञात करें |

A

a)`1/5`

B

b)`1/2`

C

c)`-1/5`

D

d)`-1/4`

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