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If sec theta= 8x and tan theta=8/x (x ne...

If `sec theta= 8x` and `tan theta=8/x (x ne 0)`, then the value of `16(x^2-1/x^2)` is:
यदि `sec theta=8x` तथा `tan theta= 8/x (x ne 0)` है, तो `16(x^2-1/x^2)` का मान क्या होगा ?

A

`1/4`

B

`1/16`

C

`1/3`

D

`1/2`

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