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A physical parameter a can be determined...

A physical parameter `a` can be determined by measuring the parameters `b, c, d, and e` using the relation `a=b^(alpha)c^(beta)//d^(gamma)e^(delta)`. If the maximum errors in the measurement of `b, c , d, and e are b_(1) %,c_(1)% ,d_(1)% , and e_(1) %`, then the maximum error in the value of `a` determined by the experminent.

Text Solution

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`a=b^(alpha)c^(beta)//d^(gamma)e^(delta).` So maximum error in a givenby
`((Deltaa)/axx100)_("max")=alpha (Deltab)/bxx100+beta(Deltac)/cc100+gamma(Deltad)/dxx100+delta(Deltae)/exx100`
`=(alpha b_(1)+betac_(1)+gammad_(1)+deltae_(1))%=(alpha+beta+gamma+delta)%`
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