The period of oscillation of a simple pendulum in the experiment is recorded as `2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s`. Find the average absolute error.

Explanation

Average value `=(2.63+2.56+2.42+2.71+2.80)/5=2.62s`
Now `|DeltaT_(1)|=2.63-2.63=0.01`
`|DeltaT_(2)|=2.62-2.56=0.06`
`|DeltaT_(3)|=2.62-2.42=0.20`
`|DeltaT_(4)|=2.71-2.62=0.09`
`|DeltaT_(5)|=2.80-2.62=0.18`
Mean absolute error
`(|DeltaT_(1)|+|DeltaT_(2)|+|DeltaT_(3)|+|DeltaT_(4)|+|DeltaT_(5)|)/5=0.54/5=0.108=0.11s`