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The length and breadth of a rectangle ar...

The length and breadth of a rectangle are `( 5.7 +- 0.1 ) cm and ( 3.4 +- 0.2 ) cm`, respectively calculate the area of rectangle with error limits.

Text Solution

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Her `l=(5.7+-0.1)cm, b=(3.4+-0.2)cm`
Area `A=lxxb =5.7xx3.4=19.38cm^(2)`
`=19.38cm^(2)=19.0cm^(2)` (rounding of to two significant figures)
`:.(DeltaA)/A=+-((Deltal)/l+(Deltab)/b)=+-(0.1/5.7+0.2/3.4)=+-((0.34+1.14)/(5.7xx3.4))=+-1.48/19.38`
`impliesDeltaA=+-1.48/19.38xxA=+-1.48/19.38=+-1.48`
`DeltaA=+-1.5`(roundign off to two significant figrues)
Area `=(19.0+-1.5)cm^(2)`
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