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The Dimensional formula of mu(0)epsi(0) ...

The Dimensional formula of `mu_(0)epsi_(0)` is

A

`[L^(-2)T^(2)]`

B

`[L^(-1)T]`

C

`[LT^(-1)]`

D

`[L^(2)T^(2)]`

Text Solution

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The correct Answer is:
A

Velocity `C=1/(sqrt(mu_(0)in_(0))),C=LT^(-1)=1/(sqrt(mu_(0)in_(0)))" "mu_(0)in_(0)=L^(-2)T^(2)`
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