In the formula `x=3yz^(2)`, x and y have dimensions of capacitance and magnetic induction respectively, then find the dimensions of y.

Options

A. `[M^(-3)L^(-2)T^(-2)A^(4)]`
B. `[ML^(-2)]`
C. `[M^(-3)L^(-2)A^(4)T^(4)]`
D. `[M^(-3)L^(-2)T^(8)A^(4)]`

Answer

D

Explanation

X=capacitance `=[M^(-1)L^(-2)T^(4)A^(2)]`, Z=magnetic induction `=[ML^(@)T^(-2)A^(-1)]`
`:.` From `X=3YZ^(2)," "Y=(XY)/(3Z^(2))=(M^(-1)L^(-2)T^(4)A^(2))/([ML^(@)T^(-2)A^(-1)]^(2))`