The velocity `v` of a particle at time `t` is given by `v=at+(b)/(t+c)`, where `a, b and c` are constants. The dimensions of `a, b and c` are, respectively.

Options

A. `[L],[LT]` and `[LT^(-2)]`
B. `[LT^(-2)],[L]` and `[T]`
C. `[L^(2)],[T]` and `[LT^(-2)]`
D. `[LT^(-2)],[LT]` and `[L]`

Answer

B

Explanation

`v=at+b/(t+c)`, As c is added to `t :.c=[T]`
at `=[LT^(-1)]` or `=([LT^(-1)])/([T])=[LT^(-2)]," "([b])/([T])=[LT^(-1)]" ":.[b]=[L]`