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In the relation y = r sin ( omega t - k...

In the relation ` y = r sin ( omega t - kx)`, the dimensions of `omega//k` are

A

`[M^(@)L^(@)T^(@)]`

B

`[M^(@)L^(1)T^(-1)]`

C

`[M^(@)L^(@)T^(-1)]`

D

`[M^(@)L^(1)T^(@)]`

Text Solution

Verified by Experts

The correct Answer is:
B
`omegat=y" " :." "omega=y/t=LT^(-1),kx=y" ":. k=L/L=1" " :. (omega)/k=LT^(-1)=M^(@)L^(1)T^(-1)`
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