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If frequency F, velocity V , and density...

If frequency `F`, velocity `V` , and density `D` are considered fundamental units , the dimensional formula for momentum will be

A

`DVF^(2)`

B

`DV^(2)F^(-1)`

C

`D^(2)V^(2)F^(2)`

D

`DV^(4)F^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
D

`P=mv=FvD`
`MLT^(-1)=F^(x)V^(y)D^(z)=[T^(-1)]^(x)[LT^(-1)]^(y)[ML^(-3)]^(z)=[T^(-x)][L^(y)T^(-y)][M^(z)L^(-3z)]`
Equating the powers we get
`z=1,y=4,x=-3`
`:.P=F^(-3)v^(4)D^(1)`
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