If `E` = energy , `G`= gravitational constant, `I`=impulse and `M`=mass, then dimensions of `(GIM^(2))/(E^(2)` are same as that of

Options

A. time
B. mass
C. length
D. force

Answer

A

Explanation

`E=[ML^(2)T^(-2)],G=[M^(-1)L^(3)T^(-2)],I=[MLT^(-1)]`
`:.(GIM^(2))/(E^(2))=([M^(-1)L^(3)T^(-2)][MLT^(-1)][M^(2)])/([ML^(2)T^(-2)]^(2))=[T]`