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During the first 18 min of a 60 min trip...

During the first 18 min of a 60 min trip, a car has avserage speed of `11ms^(-1)`. What should be the average speed for remaining 42 min so that car is having an average speed of `21ms^(-1)` for the entire trip?

A

`25.3ms^(-1)`

B

`29.2ms^(-1)`

C

`31ms^(-1)`

D

`35.6ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`V_(av)=d/t=(d_(1)+d_(2))/(t_(1)+t_(2))," "21=((1.8)(11)+(42)(v))/60impliesv=25.3m//s`
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