A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?

Options

A. `h/9` metre from the ground
B. `(7h//9)` metre from the ground
C. `(8h//9)` metre from the ground
D. `(17h//18)` metre from the ground

Answer

C

Explanation

`h=1/2gT^(2)`
At `T/3` second distance fallen `d=1/2g(T/3)^(2)=h/9`
`:.` Height from ground `=h-d=(8h)/9`