A drunkard walking on a narrow lane takes 8 steps for ward and 6 steps backward so on. Each step is 1m long and he requires 1s to travel. The time that the drunkard takes to fall in a pit 18 m away from the starting point is

Options

A. 18s
B. 126s
C. 78s
D. 62s

Answer

C

Explanation

Displacement `s=8-6=2m`
For 2m`=t=8+6=14s`
On time for `1m=7s` for `10m` time =70s
In the next 8s he covers 8 steps and falls into the pit
Total time `=70+8=78s`