A body of mass one kg is revolving in a vertical circle of radius 10m. The difference in kinetic energies of the mass at top and at bottom of the circle is given by (Take `g=10ms^(-2)`)

Options

A. 200 joule
B. 300 joule
C. 400 joule
D. 500 joule

Answer

A

Explanation

Velocity at top `F=sqrt(Rg)`, Velocity at bottom `=sqrt(5Rg)`
Difference in K.E. `=1/2m(5Rg)-1/2m(Rg),K.E.=2mRg=2xx1xx10xx10=200` joule