A parficle moves so that its position vector is given by `vecr=cos omega t hatx+sin omega haty`, where `omega` is a constant. Which of the following is true?

Options

A. Velocity is perpendicular to `vecr` and acceleration is directed towards the origin.
B. Velocity is perpendicular to `vecr` and acceleration is directed away from the origon.
C. Velocity and acceleration both are perpendicular to `vecr`.
D. Velocith and acceleration both are parallel to `vecr`.

Answer

A

Explanation

`veccv=-2omega sin omega t hatx+omega cos omega t haty, veca=-omega^(2)vecr`
Since option vector `(vecr)` is directed away from the origin so acceleration(`-omega^(2)vecr)` is directed towards the origin. Also `vecr.vecc=0impliesvecr_|_vecv`