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The position of an object moving along x...

The position of an object moving along x-axis is given by `x=a+bt^(2)` where a=8.5 m and b=2.5`ms^(-2)` and t is meaured in seconds. Its velocity at t=2 s and the average velocity between t=2s and the average velocity between t=2s and 4s is

A

`2ms^(-1),5ms^(-1)`

B

`5ms^(-1),10ms^(-1)`

C

`10ms^(-1),15ms^(-1)`

D

`10ms^(-1),20ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`v=(dx)/(dt)=2bt=5tms^(-1),` At `t=2ms^(-1),v=10ms^(-1)`
Average veocity `=x(4)-(x(2))/(4-2)=6b=6(2.5)s^(-1)=15ms^(-1)`
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