The momentum of a body increases by 50% due to change in its velocity. The kinetic energy of the body

Options

A. `125^%`
B. `50^%`
C. `250%`
D. `sqrt(50)%`

Answer

A

Explanation

Let original momentump`_1 =100prop`, Final momentum= `150 prop`
`(P_1^2)/(P_2^2)=(2mK_1)/(2mK_2)=K_1/K_2`
`((100alpha)/(150alpha))^2=(K_1)/(K_2) therefore (2/3)^2=(K_1)/(K_2)` or `4/9=(K_1)/(K_2)" " therefore K_2=(9K_1)/4`
`("Change in KE")/("Original KE")xx100=(K_2-K_1)/(K_1) xx100" " =(9/4K_1-K_1)/(K_1) xx100=5/4xx100=125%`