A bullet of mass 0.05 kg moving with a speed of `80 ms^(-1)` enters a wooden block and is stopped after a distance of 0.40 m. The average resistive force exerted by the block on the bullet is:

Options

A. `300 N`
B. `20 N`
C. `400 N`
D. `40 N`

Answer

C

Explanation

Resistive force = `("Initial KE")/("stopping distance") = (1//2 xx 0.05 xx (80)^2)/(0.40) = 400 N`