A plastic ball is dropped from a height of 1 m and rebounds several times from the floor. If 1.03 sec elapse from the moment it is dropped to the second impact with the floor, what is the coefficient of restitution?

Options

A. `0.03`
B. `0.64`
C. `0.02`
D. `0.05`

Answer

B

Explanation

The time elapsed from the moment it is dropped to the second impact with the floor is,
`t = sqrt((2h)/g) (1 + 2e)`
where h is the initial height of the body from ground
`1.03 = sqrt(2/(9.8)) (1 + 2e) , e = 0.64`