An isolated particle of mass mis moving ...

An isolated particle of mass mis moving in a horizontal plane (x-y), along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y=+15 m. The larger fragment at this instant is at

`y=-5 m`

`y=+20 m`

`y=+5 m`

`y=-20 m `

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The correct Answer is:

Since there is no external force acting on the particle hence
`Y_(CM) = (m_1Y_1+m_2Y_2)/(m_1+m_2)=0`
Hence `(m/4)xx15+((3m)/4)xxY_2=0 implies Y_2=-5m`

An isolated particle of mass mis moving in a horizontal plane (x-y), along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y=+15 m. The larger fragment at this instant is at

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